Python task to define a function that checks if a word existed in a text.. still got this code wrong

Question

text = input()
word = input()

def sch ( t , w ) :
for i in text :

if i == word :
print("Word found")
else :
print("word not found")
return
print(sch(text, word))

Answer 1

Not optimal do this:
def sch ( t , w ) :
if w in t:
a= 'ye'
else:
a= 'no'
return a
text = input()
word = input()
print(sch(text, word))

Answer 2

text = input()
word = input()
a=''

def sch(t,w):
if word in text:
a = "Word found"
elif word not in text :
a = "Word not found"
return a

print(sch(text, word))

THANK YOU ALL EVERY SINGLE COMMENT WAS JUST TOO HELPFUL ❤️❤️❤️❤️❤️

Answer 3

Hello Amr Monsef

if your funtion already print if a word is found or not, then just call this function:
sch(text, word)
Your function does not need a return statement.

And I think you don't need a loop.
if word in text:
print("Word found")
else:
print("Word not found")

Answer 4

word = input()
sentence = input()

def sub_string(w, s):
if w in s:
return "Word found"

else:
return "Word not found"

print(sub_string(word, sentence))

Answer 5

Amr Monsef
You're welcome. Also if u like to solve it with a loop do this:
t=input().split()
w=input()
def sch(t,w):
for i in t:
if i== w:
a= "Word found"
break
else :
a= "word not found"
return a
print(sch(t, w))