+ 2

Got this one on quiz ( the answer is 2359)

i=1 while i<=10: print(i+1) i*=2 # I need explanation, didn't understand the code

10th Dec 2021, 10:00 AM
Krishna Jayanth
Krishna Jayanth - avatar
6 ответов
+ 7
""" <i> = 1 Repeat while <i> <= 10 # iteration 1. <i> = (1) print <i> + 1 # output 2 <i> *= 2 # <i> becomes (2) # iteration 2. <i> = (2) print <i> + 1 # output 3 <i> *= 2 # <i> becomes (4) # iteration 3. <i> = (4) print <i> + 1 # output 5 <i> *= 2 # <i> becomes (8) # iteration 4. <i> = (8) print <i> + 1 # output 9 <i> *= 2 # <i> becomes (16) When we get here, the condition <i> <= 10 no longer satisfies, and the loop cease repetition. However, to see such output, you'd have to specify `end = ""` argument to customize the end-of-line character used by print() function. If you didn't do it, you'll see 2, 3, 5 and 9 be printed on separate lines. """ i = 1 while i <= 10: print( i + 1, end = "") i *= 2
10th Dec 2021, 11:37 AM
Ipang
+ 2
i is 1,2,4,8 each time through the loop
11th Dec 2021, 11:46 AM
Sonic
Sonic - avatar
+ 2
✓Iteration 1 Initially i is 1 So now in while loop Condition satisfies as 1<=10 So it will print 2(because i is 1 so 1+1=2) Now i value changes as i=i*2 I.e i=1*2=2 ✓Iteration 2 Now i is 2 So now in while loop Condition satisfies as 2<=10 So it will print 3(because i is 2 so 2+1=3) Now i value changes as i=i*2 I.e i=2*2=4 ✓Iteration 3 Now i is 4 So now in while loop Condition satisfies as 4<=10 So it will print 5(because i is 4 so 4+1=5) Now i value changes as i=i*2 I.e i=4*2=8 ✓Iteration 4 Now i is 8 So now in while loop Condition satisfies as 8<=10 So it will print 2(because i is 1 so 8+1=9) Now i value changes as i=i*2 I.e i=8*2=16 ✓Iteration 4 Now i is 16 So now in while loop Condition doesn't satisfies as 16>10 So it will terminate out.
11th Dec 2021, 6:04 PM
Sonali Kala
Sonali Kala - avatar
+ 1
Hi! Don’t use uppercase letters in ’while’ and ’print’. Also the answer became: 1 2 4 8 (Not 2359.) i *= 2 means i = i * 2 So the prcocess in the while loop become: [ head ] [ body ] i = 1 < 10: -> print(1); i = 1*2 i = 2 < 10: -> print(2); i = 2*2 i = 4 < 10: -> print(4); i = 4*2 i = 8 < 10: -> print(8); i = 8*2 i = 16 !< 10: -> stop loop!
10th Dec 2021, 10:33 AM
Per Bratthammar
Per Bratthammar - avatar
0
Start i=1 The while loop will iterate as the value of i is <=10 And print(i+1) that is 1+1 = 2 Now i will increment as i = i*2 every time So according to this iteration the values of i after every incrementation i = 1,2,4,8 And will print i+1 that is 2359
11th Dec 2021, 7:21 PM
Sujeet Tiwari
Sujeet Tiwari - avatar
- 1
well when you made a loop with while and the condition stops at10 according to youre code the i wil accrese until it reach 10 and then the i will be multiple 2 until it reach 10 if the number it reached isnt 10 it will asign the number before it so according to youre code the output is: 0 1 2 3 4 5 6 7 8 9 and the i *=2 wont output untill you print it but it will be like this 0 2 4 6 8 10
11th Dec 2021, 1:01 AM
loki
loki - avatar