How to sum multiple values to existing key of the dictionary In one line

Question

l = list(map(str,input().split(',')))
d = {}
d = {l[i+1].upper() : (int(l[i]) if l[i+1] not in d else d[l[i+1]]+int(l[i])) for i in range(0,len(l),2)}
print(d)
#input : 101,p,102,o,302,p,305,p

Anyone, please tell me how to add value to the existing key of the dictionary in one line, in the above code value is updating to a key but it is not adding can you solve it for me, please.

Answer 1

Make the dict with uneven keys with default value of 0.

Iterate over keys and vals while updating the value of the key.

https://code.sololearn.com/cx0i5Lmt35C7/?ref=app

Answer 2

It's simple
d.__setitem__(x, y) equal d[x] = y
d.get(x, 0) the second is the default return value if not find the key x, there is a zero passed

And we can't use d[x]=y to assign the value in the list comprehension

Answer 3

You means the letter is the key?

Answer 4

l = list(map(str,input().split(',')))
d = {}
[d.__setitem__(l[i+1], int(d.get(l[i+1], 0)) + int(l[i])) for i in range(0, len(l), 2)]
print(d)

Answer 5

Thank you so much bro 🥰

Answer 6

I need output as {'p': 708, 'o': 102}
But I getting this output {'p' : 305, 'o' :102}

Answer 7

The p value is not adding its just updating thats my problem I need add the value to p key

Answer 8

Yes the letter is the key

Answer 9

Bro It shows attribute error

Answer 10

I am not your level bro i can't understand what it is

Answer 11

Oh ok bro, but its not working bro plz check for me in compiler

Answer 12

By the way, thanks for explaining 🤗

Answer 13

It works well with your input above.

Show the wrong prompt and input output

Answer 14

Ok bro and thanks for your response bro I will check again tomorrow morning now I am going to sleep, bye bro.

Answer 15

arsh