Find and replace a word in a string and count how many replacements occurred? What’s the wrong in my code or any solution?

Question

text = "Amy has 128 dollars, while David has 54 dollars. Amy is going to the zoo. David watches soccer."

f = input()
r = input()
c =0

while(text.find(f))!= -1:
text = text.replace(f,r)

for w in text.split():
if w == r:
c = c +1

print(c)
print(text)

Answer 1

Md.Delwar Hossain

First count then replace.

also in case of text.split() will not work because in this case "dollars," or "dollars." would be considered as a string means comma and dot will also be join with string so

'dollars' == 'dollars,' # would be false

So

Simply you can use count function and replace function directly without loop

print (text.count(f))
print (text.replace(f, r))

Answer 2

Thanks. My problem is I always think complex way where there is a simple solution available.