How to test if a float number exists between two int numbers?

Question

Lets say the number is 4.5 and we want to see if its between 1-10.
x = 4.5
If x in range(1,11):
Print(”exists”)
Else:
Print(”none”)
This Would surely not work.

Answer 1

Lenoname use the comparison operator <.

if 1<x and x<10:

Python also lets you shorten that to this:

if 1<x<10:
print("exists")
else:
print("none")

Answer 2

Start and stop arguments should be separated using a comma in range()
Btw, range() doesn't return floats.
Better you try using numpy arange in this context.

Answer 3

Try this
import numpy
print(numpy.arange(1,11,0.5))
print(numpy.arange(1,11,0.01))

if statement is executed, if x is included in array otherwise it moves to else part.

Answer 4

Step argument takes 1 by default means if it's not provided its value is 1.
So, numpy.arange(1,11,1) returns 1,2,...10
To include floats, you can do it like this
numpy.arange(1,11,0.5)

Answer 5

Simba If x in numpy.arange(1,11):
print(”exists”)?

Answer 6

Simba And if its 4.01 then it should be numpy.arange(1,11,0.01) i suppose or is it enough with 0.5?

Answer 7

def number_exist(fnum, num1, num2):
return 'exists' if num1<fnum<num2 else 'none'

Answer 8

Try int(x) instead of x