Give me a hint please

Question

i try to solve this problem:
You’re making a calculator that should add multiple numbers taken from input and output the result.

The number of inputs is variable and should stop when the user enters "stop".

my code is:

sum = 0

while True:

x = int(input())

sum = (sum+x)

print(sum)

if x == "stop":

break

print(sum)

i understand that "stop" isnt a number, and that is why my code doesnt work. But How to present it as number? give me please a hint

Answer 1

sum = 0
while True:
x = input()
if x == "stop":
break
sum += int(x)
print(sum)
print(sum)

Answer 2

You can take x as string input and cast it to integer using int() in addition.

Answer 3

Flow of control. The int() is encountered before 'if...break' and it raises error. , Because int() can't function on strings like 'stop'

Answer 4

Find a way to first process the input as a string for instance

while True:
x = input()
if x=="stop":
break
x = int(x)

Answer 5

Yyyyyyyyyyyyyyy😀😀😀😀😀😀

Answer 6

In the while loop you could first test if == „stop“ and handle this as you that did below.

Answer 7

x = input()
sum = sum + int(x)
And try using if-else statement instead.

Answer 8

sum = 0

while True:

x = input()

sum = sum+int(x)

print(sum)

if x == "stop":

break

print(sum)

this one doesn't work, whats wrong

Answer 9

You only need to print sum outside loop as a final value.
And, do calculations after if block.

Answer 10

You need to use if block before using int() function.

It's the flow of control. It will raise error when it encounters int() if it's a string

Answer 11

why if block before sum = sum+int(x)?

Answer 12

Convert x to an int after checking if it equals 'stop'.

You can store it in a variable or just use
sum += int(x)
Because we don't use the int value of x anywhere else

Answer 13

https://youtu.be/ue2oBTqGaIs

Answer 14

like this
x = int(input())
x = input()
?

Answer 15

x = int(input())

y = input()

is this possible?

Answer 16

Porque un int no debe recibir string

Answer 17

sum =0

while True:
x = input()
if x.isnumeric():
sum +=x
else:
if x == "stop"
break

Answer 18

olli

You cannot get a while loop input to work properly here in Sololearn.

while True:
x=input()

will not work here.

All inputs are processed all in one go at the submit popout box.

That is why python codes that need repeated inputs like the hangman game or number guessing game are not possible here.

Maybe a workaround?

https://code.sololearn.com/c3m89XkQAq7G/?ref=app

Answer 19

I need to make some $$

Answer 20

Try this

sum = 0
x = int(input())

while not x==“stop” :
sum+=x
x = int(input())

print(sum)

Tell my if it’s not work .