I have asked my questions in the form of comments in below code.

Question

https://code.sololearn.com/crkqpkz7Z7ep/?ref=app

Answer 1

- Step number 1 : n=39 , i=2 ==> The method does not return a value .
- Step number 2 : n=39 , i=3 ==> The method returns the value of 0 .
- Step number 3 : n=23 , i=2--11 ==> The method does not return a value .
- Step number 4 : n=23 , i=12<23/2 ==> Get out of the loop and The method returns the value of 1 .

Answer 2

This loop will never loop. The if statement in the loop has a return, which will break out of the loop. So in the first iteration it will go through the if statement and exits with 1 or 0.
https://code.sololearn.com/cLJ0ezVG1l1a/?ref=app

Answer 3

In line 5 for the first iteration n=39 does the for loop ends bcs of 39%3=0(i=3)as return 0 is given.

Answer : yes

Answer 4

Nicely done.

Can you add some debugging lines to your code to see what's happening?

Eg: cout << i;
https://code.sololearn.com/cL7hvbePb5xw/?ref=app

Answer 5

- Step number 5 : n=49 , i=2--7 ==> The method returns the value of 0 .
- Step number 6 : n=2, i=2<2/2 ==> Get out of the loop and The method returns the value of 1

FINISH