C++ Module 2: Countdown Challenge

Question

Hello Everyone!

Wanted to check if someone could make my code more efficient? Thanks!

QUESTION: You need to make a countdown app.
Given a number N as input, output numbers from N to 1 on separate lines.
Also, when the current countdown number is a multiple of 5, the app should output "Beep".

Sample Input:
12

Sample Output:
12
11
10
Beep
9
8
7
6
5
Beep
4
3
2
1
https://code.sololearn.com/c99WSLtnV0Au/?ref=app
https://code.sololearn.com/c99WSLtnV0Au/?ref=app

Answer 1

This is my solution, there are many other solutions that works the same and are as effective.

int main() {
int n;
cin >> n;

for(int x=n;x!=0;x--){
cout << x << endl;
if(!(x%5))
cout << "Beep\n";
}

return 0;
}

Answer 2

For this task thats basically as efficient as it can be.

Answer 3

Yeah, if statement takes a bool which means everything bigger than 0 is true. and the ! reverses the bool so true = false, false = true. So when the x%5 is equal to 0 it means false and ! makes it true so the statement can happen.

Answer 4

Thank you for confirming 👍

Answer 5

Nice code mate.

Is it supposed to print both beep & the multiple of 5? Or should it replace the multiple of 5 with the beep?

You couldn you use a ternary to make the if print a line or 2 shorter, us that something you are interested in trying?

Answer 6

Thanks for your response!
Yes, it's supposed to print both.
I am yet to learn what a ternary is! I would definitely be interested 😊

Answer 7

Ooh I really appreciate your example! I just learnt about the "!" Logical operator, it's really cool! Thank you 😊