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error: expected primary-expression before 'float'
Hey guys I'm new to c++ and I don't know what I'm doing wrong.Can anyone help please. #include <stdio.h> #include <math.h> int main() { float y, x; float root1, root2 float root_part, root_denom printf('Enter the values of y, x'); scanf('%f%f', &y, &x); root1 = 2.0 * cos (y * y * sqrt(2.0 * x)); root_part = 4.0 * x + 3.0; root_denom = 3.0 * x * x + 2.0 * y + 4.0; root2 = sin * y f = root1 + ( root_part / root_denom ) + root2 printf('f = %.3f', f) return 0; }
7 ответов
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You are using [ ] squire brackets but need to use curly brackets { }
int main{
// code
}
put semicolon ; at the end of each expression.
and use double quotes " " in printf....
edit: TaJoX
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If you want run this in c++ here, then add iostream header and ask input by cin>>y>>x; instead of scanf(".. ") ;
then it works fine.
don't change original question.. add updates in reply, if you need..
hope it helps..
+ 1
okay thank you I'll try to change it
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I changed it but I still get error messages
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I don't know what's wrong but it stil doesn't work
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#include <stdio.h>
#include <math.h>
int main()
{
float y, x;
float root1, root2;
float root_part, root_denom;
printf("Enter the values of y, x"); //1
scanf("%f%f", &y, &x); //2
root1 = 2.0 * cos(y * y * sqrt(2.0 * x));
root_part = 4.0 * x + 3.0;
root_denom = 3.0 * x * x + 2.0 * y + 4.0;
root2 = sin(x * y); //3
float f = root1 + ( root_part / root_denom ) + root2; //declare f
printf("f = %.3f", f);
return 0;
}
/*
but it's a complete c code. Works in c++ also. But not properly work for input taking here , unless you have a cin. run it in c.
In your code, corrected mistakes are :
//1, 2 : are wrong quotes errors
//3 : is incomplete sentence
f is undeclared
*/
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You're welcome..