Create a classic FizzBuzz program in python that loops from 0-100 and outputs FIZZ when the number is even, Buzz when the numbe

Question

HERE'S MY SOLUTION.. PLEASE HELP
.
.
https://code.sololearn.com/cy3EiBm1av2x/?ref=app

Answer 1

https://code.sololearn.com/cTm0CZyHq3h2/?ref=app

Answer 2

Mirielle i have attached the link.. Please help

Answer 3

Now pls edit the question telling us what help you need

Answer 4

It skips past required numbers 0 and 1.

The for loop in is_prime always exits in its first iteration. That is because both branches of the if/else statement inside the loop end with a return statement. The break statement after the return is unreachable.

There is unnecessary logic and unreachable code in the Fizzbuzz function.

Below I have reduced the code and put it into workable condition:

#MY FIZBUZZ
#Define a prime number

def is_prime(x):
if x <= 1:
return False
for primes in range(2,x):
if x % primes == 0 :
return False
return True

def Fizzbuzz(Number):
for y in range (0, Number+1):
if is_prime(y):
print (f"{y} FizzBuzz")
elif y % 2 == 0:
print ("Fizz")
else:
print ("Buzz")

Fizzbuzz(100)