Why does my program hv no output

Question

#include <stdio.h>
#include <stdlib.h>

int main()
{

float x = 1.1;

while(x == 1.1)
{

printf("x = %f",x);
x = x - 0.1;

}

return 0;
}
https://code.sololearn.com/ckongjTmvl2r/?ref=app

Answer 1

Zane Vijay Falcao

Yes

You can read answer here about why both are not equal

https://www.quora.com/What-is-the-difference-between-float-and-double-in-C-language-How-is-it-stored-in-the-memory?top_ans=14244454

Answer 2

Zane Vijay Falcao

If you use double instead of float then condition will be true

double x = 1.1;

if (x == 1.1) //true

float y = 1.1;

if (y == 1.1) //false

Answer 3

Zane Vijay Falcao

Both x = 1.1 and 1.1 seems equal but that's not

So do this:

while (x > 1.1)

Or do this:

while(x == (float) 1.1)

Answer 4

Thanks

Answer 5

It seems you have an infinite loop, then execution gets aborted. Pls link your code from Code Playground into the question (edit the question) for us to see the exact response.

Answer 6

Done Emerson Prado

Answer 7

It is really an issue of precision.
Pls read here a good reference on comparing float values:
https://www.tutorialspoint.com/what-is-the-most-effective-way-for-float-and-double-comparison-in-c-cplusplus

Answer 8

The question is to predict the output n explain Y don't get a output

Answer 9

The value of test condition is true so it should execute the printf statement

Answer 10

(float) means type casting right??

Answer 11

Erm no idea

Answer 12

try this:
printf("%d\n", x==1.1)
x==1.1 is 0
while(0) will never get executed.

Answer 13

trt while(x<=1.1)

Answer 14

it may be because you used == symbol inside the while