I have number(N) and i have to print all the number between 1 to square of that number(N*N)

Question

function patternOfN(N) {
for(i=1;i<=N;i++){
let s = "";
for(j=i;j<=i*N;j++){
s = s+j+" ";
}
console.log(s);
}
}

input is 4

desire output
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16

but what i get
1 2 3 4
2 3 4 5 6 7 8
3 4 5 6 7 8 9 10 11 12
4 5 6 7 8 9 10 11 12 13 14 15 16

so where i am wrong ?

Answer 1

count=0;

    for(i=1;i<=N*N;i+=N){

        count+=1;

        let s = "";

   for(j=i;j<=count*N;j++){

       s = s+j+" ";

   }

   console.log(s);

    }

here I solve this

Answer 2

TINKLE DASH

Check step by step and read carefully

It will print

Answer 3

Manav Roy but I have to put that as row and column

Answer 4

TINKLE DASH

Use a 3rd variable

function patternOfN(N) {
var k = 0;

for(i = 1; i <= N; i++) {
let s = "";

for(j = 1; j <= N; j++) {
k++;
s = s + k + " ";
}

console.log(s);
}
}

patternOfN(4)

Answer 5

TINKLE DASH You can just break lines on every output which is multiple of the input.
Or, if you prefer nesting, do both loops from 1 to N. Then output the sum of i * N and j. This way, every line gets incremented by N, which is what I guess you need (the description isn't clear).

Answer 6

Ah, it's solved already. Didn't get it from last message.

Answer 7

A͢J it print nothing

Answer 8

So loop from 1 to N*N. No need for nested loops.

Answer 9

Emerson Prado but I need to be print it in a tabular form

Answer 10

Emerson Prado how can I break line of input can you give me the solution

Answer 11

You can add a line break - '\n' - where needed

Answer 12

Emerson Prado but it's just for input 4
It's not a generic code for every input

Answer 13

TINKLE DASH The function you wrote is generic - it has parameter N exactly for that.
But what difference does it make?

Answer 14

Emerson Prado the pattern what I want is
****
****
****
****
But I get here
*
**
***
****
For that I try to rectify inside the function
count=0;

    for(i=1;i<=N*N;i+=N){

        count+=1;

        let s = "";

   for(j=i;j<=count*N;j++){

       s = s+j+" ";

   }

   console.log(s);

    }

here I solve this

Answer 15

You're quite close to the solution, but the communication is being incomplete. So let's do it the right way:
1. Save this code in Code Playground
2. Include a link to it in the question description
3. Include the whole output in the question description
4. Explain your current difficulty in the question description
5. Remove all code from the question description
Then, I can see exactly where you are and suggest the next step.

Answer 16

Emerson Prado

https://code.sololearn.com/c65FH4dhocKp/?ref=app

Answer 17

Yup 😊