+ 2
Can anyOne figure this out?
The snail climbs up 7 feet each day and slips back 2 feet each night. How many days will it take the snail to get out of a well with the given depth? Sample Input: 31 Sample Output: 6 Explanation: Let's break down the distance the snail covers each day: Day 1: 7-2=5 Day 2: 5+7-2=10 Day 3: 10+7-2=15 Day 4: 15+7-2=20 Day 5: 20+7-2=25 Day 6: 25+7=32 So, on Day 6 the snail will reach 32 feet and get out of the well at day, without slipping back that night
11 ответов
+ 3
Yes, but what exactly do you need help with?
+ 2
It's giving you the math in the task description. You wrote it out.
0
This is The Hint 👇🏻
Hint: You can use a loop to calculate the distance the snail covers each day, and break the loop when it reaches the desired distance.
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the Math 😅😁
0
Justice ??
0
the problem is i don’t know wrote what where
Justice
0
nothing
0
You can try this as well
n is the input
7x - 2(x - 1) = n
x = (n - 2) / 5
result -> x + (x % 5 != 0)
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i = 0;
for (; depth > 0;) {
i++;
depth -= 7
if (depth > 0) {
depth += 2
}
}
console.log(i);