Please explain comparison of negative number

Question

#include <stdio.h>
int main(){
int a=10, b =13, d=13, k=-1, c;
c= sizeof(long double) < -3-k || b==d && b<a;
printf("%d", c);
return 0;
}

Answer 1

The code is only evaluating 'sizeof(long double) < -3-k' this returns true, or 1. The rest is ignored because there is no need to check because of how '||' works.

sizeof returns an unsigned number so -3-k has to be converted to an unsigned number as well. Since -3-k is a negative number the resulting non-negative number is a very big number and the size of a long double is of course less than that big number.

Answer 2

Negative values, and any non-zero values in general, are treated as true when used as conditions

C= size(long double) < (-3-k || b==d && b<a);

->&& operator return true if both condition are true
Hence b<a is false
-> || condition return true if one of statement is true
-3-k is negative and non zero number so it is treated true
True ->1

Answer 3

Compare that with sizeof(long double )

Answer 4

Akshay,
What are you trying to calculate here?

Answer 5

Akshay Bhujbal sizeof(long double) = 16
16<1 :: false..
So answer is zero

you put ques like in bracket

Answer 6

Answer is 1 you can run it

Answer 7

Akshay Bhujbal ya but without bracket you can check it ..
Further now you got the output..

Answer 8

Okay, thank you for the explanation

Answer 9

The question was find the output

Answer 10

Question was not asked with bracket