what would be the output of the snippet code c++ and how would it be like that?

Question

#include <iostream>
using namespace std;

int main() {

typedef struct {char ch;} st;
st s1={'c'};
st s2=s1;
if (s1==s2)
cout<<"sucessfull";

return 0;
}

https://code.sololearn.com/cuIdQ76ZDd6s

Answer 1

Errors, your syntax is wrong.

https://code.sololearn.com/ctQoSlF3LwpL/?ref=app

Answer 2

so you are asking what something like this:

char s1{'c'};
char s2{s1};
if(s1==s2) cout << "successful";

would be? From your naming convention I assume you think these are some kind of "string", which they are not. The char is really almost exactly the same as an unsigned int8_t. Think about the logic with a regular integer, it would be the same value right? So the output would be "successful".

Please notr that you can overload the == operator in C++. This is also often done in string classes. So even having s1 and s2 as std::string would result in the same out, even though they do have different mempry locations. That is a difference to languages like java, where you have to implemnet a method to compare two reference types. In C++ you can implement the operator for these types yourself directly. In java this operator would just compare the reference/pointer.
In C++ you are always working with values though! Except you are using pointers. But be aware the string classes will have pointers as members

Answer 3

I have made your code runable and did some small changes:

https://code.sololearn.com/cK2t4yn5ydFG/?ref=app