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Why my code is still giving an error after using try and except ?

try: def b(c, d, e="abc", f): print() print(c, d, e, f) b(2, 4, 5, f) except: print("default argument shouldn't be followed by non-default argument")

30th Sep 2022, 3:28 AM
Shantanu
Shantanu - avatar
2 ответов
+ 1
Shantanu understand that try/except only operates during run time so it can catch only run-time exceptions. What you show is a syntax error, which occurs during parsing/interpretation time. There is a trick you can use to turn this into a run-time error. That trick is to use eval(). Place the code you want to trap for syntax error into a string, and pass it into eval(). The code will not be parsed until run time. Try/except will trigger a SyntaxError error when eval gets executed. What I show below also uses a trick using docstrings ("""... """ -- surround your code with three double quotes) to let you define a multi-line string. try: eval(""" def b(c, d, e="abc", f): print() print(c, d, e, f) b(2, 4, 5, f) """) except: print("default argument shouldn't be followed by non-default argument")
2nd Oct 2022, 3:40 PM
Brian
Brian - avatar
+ 4
You need to change sequence of parameters try: def b(c, d, f ,e="abc"): print() print(c, d, e, f) b(2, 4, 5, f) except: print("default argument shouldn't be followed by non-default argument")
30th Sep 2022, 4:02 AM
A S Raghuvanshi
A S Raghuvanshi - avatar