55 Code Project Shapes

Question

I have no idea what I am doing wrong, also I don't know how to use Math.PI so I used the numbers 3.14159 instead

import java.util.Scanner;

abstract class Shape {
int width;
abstract void area();
}
//your code goes here

class Square extends Shape {
public void area(){
int Sq_answer = x*x;
System.out.println(Sq_answer);
}
}
class Circle extends Shape {
public void area(){
Double Cir_answer = 3.14159*y*y;
System.out.println(Cir_answer);
}

}

public class Program {
public static void main(String[ ] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
int y = sc.nextInt();

Square a = new Square(x);
Circle b = new Circle(y);
a.area();
b.area();
}
}

Answer 1

In Java, you can use the constant Math.PI to get the value of π with more precision than using a hard-coded value like 3.14159.
Double Cir_answer = Math.PI*y*y;

Answer 2

Thanks so much, but this code is not working yet, I'm getting an error that it can not find the symbol and it's pointing to the y and x variables. Here is the only change I made to the code above:
Double Cir_answer = Math.PI*y*y;