Palindromic Headache 🤕🤕

Question

Please someone should help explain to me how this code block to check whether a number is palindromic works. Thanks.

do
{
digit = num % 10;
rev = (rev * 10) + digit;
num = num / 10;
} while (num != 0);

Answer 1

this example will explain
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int num=15634;
int digt=0;
int rev=0;

do{
//first loop
digt =num%10;
//digt=4
rev=(rev*10)+digt;
//0+4=4
num=num/10;
//num=1563 loop will continue

/* //second loop loop will continue
digt =num%10;
//digt=3
rev=(rev*10)+digt;
//40+3=43
num=num/10;
//num=156 loop will continue

//third loop
digt =num%10;
//digt=6
rev=(rev*10)+digt;
//430+6=436
num=num/10;
//num=15 loop will continue

and so on;
until loop finished
the rev will be 43651
and it's not palindromic
*/
} while (num!=0)
cout <<" number is :"<<rev<<endl;
return 0;
}

Answer 2

DevAbdul
Here's is another example which may help:

https://code.sololearn.com/ceN1PeIF7RBb/?ref=app

Answer 3

Thanks for your help, I really appreciate it.