Need solution

Question

int x=0;
int y=2;
do{x+=y;}
while(x<4);
Syste.out.print(++x);
How the output is 5?
It should 3...

Answer 1

Initially, the value of x is 0. The do while loop will execute until the condition in while is met. Here the loop will execute twice, i.e., the value of x will become 4. Then, since x = 4 the condition in while is not satisfied as x is not less than 4 and the loop will end. Next you're outputting the value of x after incrementing it by 1. Therefore, the value of x = 4 + 1 = 5.