Please give me Explaination for below Program:

Question

x = 1
while x < 10:
x += 1
if x%2 == 0:
print(str(x) + " is even")
else:
print(str(x) + " is odd")

Answer 1

Iynesh Karthick ,

2 small amendments that improves the code a bit:

> the number of 1 will not be processed and not *output* since the increment is done just *before* the calculation. do this after the
if... else... construct. if you wanted to include the number of 10, use: while x <= 10:

> the output of the numbers does not need to be converted to string, if we use the comma notation instead of concatenation with *+* operator.
also no extra space is needed in the strings.

x = 1
while x < 10:
#x += 1
if x%2 == 0:
print(x, "is even")
else:
print(x, "is odd")
x += 1

Answer 2

Iynesh Karthick it's a simple odd or even while loop .. not sure why you are changing a number to a str when you can simply use
print(f"{x} is even")
and the same with your odd print

Answer 3

# create variable x and assign it to 1
x = 1
# this is while loop , its iterate the cods inside of it x Less than 10
while x < 10:
# increase value of x by 1
x += 1
# if x can be divide by 2 with 0 remainder i.e x is even number then print x is even
if x%2 == 0:
print(str(x) + " is even")
else:
print(str(x) + " is odd")
#else print x is odd