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[*string] vs list(string)
Okay, imagine i have a string, say 'abc def'. If i want to split it into individual characters, i could do [*string] or i could do list(string) which output the same thing ['a', 'b', 'c', ' ', 'd', 'e', 'f']. I was wondering, without using split, a) are there other methods that could work b) what is the difference between list(string) and [*string]? Can they be used interchangably and which one is more readable?
4 ответов
+ 3
Edited with errors rectified as pointed out by Rain.
You can use a for loop to split it up if you want more control. You can then choose to omit the space (or any other character).
string = "abc def"
list = [ ]
for char in string:
if char == " ":
continue
list.append(char)
print(list)
This also works the other way.
list = ['a', 'b', 'c', ' ', 'd', 'e', 'f']
string = ""
for char in list:
if char == " ":
continue
string += char
print(string)
+ 3
StuartH ,
list ['a', 'b', 'c', ' ', 'd', 'e', 'f']
should be
list = ['a', 'b', 'c', ' ', 'd', 'e', 'f']
and
for char in string:
(the second time) should be
for char in list:
It's inconvenient that you can't flip over to the Code Playground when writing a comment to test for typos.
I used to use the playgrounds of various websites, such as w3schools.com, for that. Now I have Pydroid 3 on my Android phone.
There's a risk using list as a variable name, because that's already the name of the constructor for the list class.
If you later try to use that constructor,
befuddled = list("flabbergasted")
you'll get,
TypeError: 'list' object is not callable
Since list isn't a keyword, you won't get a SyntaxError when assigning to it. Python will happily overwrite the identifier with a new reference. I suspect some IDEs warn you about names like that, but Pydroid 3 doesn't, so I'm learning what to avoid little by little.
+ 2
# I like this trick:
print(*"spaced") # s p a c e d
0
Stuart, yes, i could, but it wont be that compact. Alas, i want it to be readable