Why this output is "1"?? please explain....

Question

#include<stdio.h>
int main()
{
int x=5, y=10, z=10;
x=y==z;
printf("%d", x);
return 0;
}

Answer 1

because you are assigning an expression so y == z its true so true == 1

Answer 2

#include<stdio.h>
int main()
{
int x,y=10;
char z='a';
x=y+z;
printf("%d", x);
return 0;
}

Output??

Answer 3

it gives you 107 because it is taking the ASCII of 'a' that is 97 so you got x = 10 + 97 = 107

Answer 4

thank you.

Answer 5

is 'single_quotation' meaning of ASCII number? does it ('a') has another meaning??

Answer 6

actually 'a' is a character but as the variable that gets the result is of type int you can't concatenate 10+'a' that's​ why it takes the ASCII number