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6 ответов
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How about i tell you a very close logic and you try coding it?
Here's my logic:
1. Traverse through each character of string using loop
2. using isupper() and islower() function you can determine whether character is lower or upper
3. Using conditional count upper and lower characters in different variables
4. Then using conditional outside the loop compare which one is more and print the required result
You ask further questions on my explanation in same thread but it would be better if you can find syntax by yourself cause it'll help in learning
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clet onwumere ,
> what about if number of lower case is equal to number of upper case ?
> what about whitespaces, digits or special cases, they are neither uppercase nor lowercase ?
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clet onwumere Snehil's solution is a good solid one.
Alternatively if you are looking to get more practice with regular expressions, you could find all matches for regular expression matching upper case letters, and separate find all matches for lower case letters. Then compare the lengths of both results.
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In Snehils step 2 you could use the ord() function instead of isupper() and islower().
• Upper case for 64 < ASCII value < 91
• Lower case for 96 < ASCII value < 123
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Brian M. Why not without ord?
Just check with characters cause the comparison is lexicographic
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