Fastest way to find the largest number in an unsorted array?

Answer 1

Dunno about "fastest", but could just do a for loop that compares the index to a variable, if it's higher, it saves the index value as the variable value. The variable will keep changing as the numbers get higher until you're left with the biggest number in the array.

public class Program
{
public static void main(String[] args) {
int[] x = {2, 7, 9, 2, 6, 4, 13, 3, 7};
int compare = 0;

for(int i : x){
if(i > compare){
compare = i;
}
}
System.out.println(compare);
}
}

Answer 2

@SUCHIT it's an enhanced for loop. It cycles through the array with i being set as the value of the each index as it cycles through.

Answer 3

for(int i : x) means?

Answer 4

What about using thread?

Answer 5

use ".Max()" after the array nsme.