why this code will print 0

Question

def print_nums(x):
for i in range(x):
print(i)
return
print_nums(10)

Answer 1

In the first iteration of the loop, i is 0 and this will be printed. Then the return statement is called and the function execution stops.

Answer 2

range(n) is composed of all the whole numbers between 0 included and n exluded : ie range(10) is composed of 10 numbers : 1,2,3....,8,9

so in your code, in your function the i in the for loop will take all this value one per one, ob tge first iteration i=0 then i=1 etc...

but on the first iteration i=0 then you have print(i) so 0 is output and then you have the return statement that is the end of the function. So when pytgon reads return he finishes the function. So the for loop will never repeat because of the return statement.

If you want all your values printed, then you have to set the return keyword after the for loop and not inside (with the right number of instrumentations)

Answer 3

sorry but can you tell more clearly

Answer 4

Thanks I finnaly understand!!!!!!! Thanks a lot inded!!!!!!

For real, my man!!!

Answer 5

ok
now i got it
thank you to both of you
for helping me