Why this code prints output yes ?

Question

x=True
y=False
z=False
if x or y and z:
print("yes")
else:
print("no!")

this is how i thought it is evaluated
x or y and z
True and z
that is. True and False
results to False

where am i wrong?

Answer 1

with "or" if one operand is true then all the statment is true.

you can see the above expression as below:
x or ( y and z )
=> true or ( false and false)
=> true or false
=> true
we get that the statement is true, then it will print "yes"

Answer 2

According to Python documentation, the operators precedence as follow:
First is 'not x', then 'and', then 'or'.

Reference (see towards the page bottom):
https://docs.python.org/3/reference/expressions.html

Answer 3

Operator precedence, the AND is executed first then the OR.

First AND then OR then NOT.

Answer 4

cx=True
y=False
z=False
if x and y or z:
print("yes")
else:
print("no!")
>>> now it will print no.