+ 1

Why is this the outcome?

The outcome of this code is 012024, but I really don't understand why. Could someone explain it to me? for(int i = 1; i < 3; i++){ for(int j = 0; j < 3; j++){ if(i + j > 5) break; System.out.print(i*j); } }

9th May 2017, 3:41 PM
Maart
Maart - avatar
3 ответов
+ 2
1st outer loop: 1st inner loop: i=1, j=0, i*j=0 2nd inner loop: i=1, j=1, i*j=1 3rd inner loop: i=1, j=2, i*j=2 4th inner loop: j would no longer be <3, so the requirement is not fulfilled 2nd outer loop: 1st inner loop: i=2, j=0, i*j=0 2nd inner loop: i=2, j=1, i*j=2 3rd inner loop: i=2, j=2, i*j=4 4th inner loop: same as above 3rd outer loop: requirement is not fulfilled, so your program will not enter the inner loop anymore and your break-condition is never reached! So your program is done.
9th May 2017, 3:50 PM
Patrick Schieber
Patrick Schieber - avatar
+ 4
1. i=1, j=0 . Here i+j is not > 5, Hence break is not executed. i*j is printed = 0 2. i=1 j=1 same blah blah, i*j = 1 . NET OUT= 01 3. i=1, j= 2 same blah blah , i*j = 2 NET OUT=012 Inner Loop terminated,outer incremented 4. i=2 j=0 same , i*j=0 NET = 0120 5 i=2 j=1 same , i*j = 2 net=01202 6. i=2 j=2 same , i*j =4 net = 012024 inner terminated, outer terminated. Loops terminated. Answer: 012024 If statement never works.
9th May 2017, 3:53 PM
Meharban Singh
Meharban Singh - avatar
+ 1
Thanks, it all makes sense now!
9th May 2017, 4:11 PM
Maart
Maart - avatar