int x = 1/ 3; cout << x; // Outputs 0 . Why?

Answer 1

x is an integer. By default, the fractional/decimal part will be taken off, basically resulting in a floor. So .333333... The decimal will be taken off and now it is 0.

Answer 2

x is an integer, it cant store decimal places. 1/3 gives 0.33333... , and it cant store that, hence it rounded down to 0.

Answer 3

integers dont round. they truncate. The decimal places go to a digital void never to be seen again

edit:
example. we store 4.99 into an integer.
we look at it and it says it is 4. Why? because integers cut off everything after the decimal place

Answer 4

X is an integer... Because of that you get only the integer part of 0.33333.... It is 0.

Answer 5

Because x is int and the integer part of 1/3 is 0. If you want to print 0.333 ... use variables of floating type.

Answer 6

actually 1/3 result is 0.3333333..but return type of x is declared int. so,output is 0.

Answer 7

use float x instead of int x

Answer 8

use float not int.

for ex:

float x;
x = 1/3;

cout<< x <<endl;

Answer 9

0