+ 2
Handling errors inside except block
try: print(1) print(10 / 0) except ZeroDivisionError: print(unknown_var) except NameError: print('Filtered an error from the first except block') finally: print("This is executed last") I intended to filter the error within 'except ZeroDivisionError' block but failed. How can I print the string in the second except block?
1 ответ
+ 3
Is this what you are trying to do?
Code:
try:
print(1)
print(10 / 0)
except ZeroDivisionError:
try:
print(unknown_var)
except NameError:
print('Filtered an error from the first except block')
finally:
print("This is executed last")