How output getting for this

Question

int a=2;
int b=3;
a+= ++a * b;
cout <<a;

Answer 1

12
1. ++a=3
2. ++a*b=9
3. a+=++a*b=12
C++ starts to process from immediately right side of an equivalance

Answer 2

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Answer 3

1. x+=x means x=x+x
2. So a+=++a*b means a=++a*b+a

Answer 4

int a,b;
a=2; // ++a=3 value of a now used is 3
b=3;
a+=++a*b; /*you can interpret it as........
x+=(something);
is equivalent to
x=x+(something);
Same applicable here as
a+= ++a * b;
is equivalent to
a= ++a + (++a*b);
so you'll be getting a= 3+(3*3)=12*/

Answer 5

lil confused with third line.. result of ++a*b=9.. ok..but how dat 9 becomes 12 when operates with "a+=" in the 3rd line..
how dat a+= (I think itz equivalent to ++a) works here

Answer 6

No actually not if a variable's value incremented by preincrement operator it effects the value throughout scope hence a's initial value becomes 3 and remains so unless changed.

Answer 7

Thank you!

Answer 8

:)