why this output 5 and why not 2? #include <iostream> using namespace std; void func(int &x) { x=5; } int main() { int x=2; func(x); cout<<x; }

Answer 1

because you call the function func() and his reference as argument is the variable x inside the function that have value 5...when we call the function...the function pick the reference variale x inside of that function...not the variable on main() function...hope that this helps ;-)

Answer 2

Not at all...hey have you whatsapp...if you have lets have some programming chat at there...would be interesting and I will be honored

Answer 3

thank Carlos

Answer 4

yea, what's your WhatsApp no.

Answer 5

its from Brazil. .. here: [phone]

Answer 6

and your no.?

Answer 7

[phone]