Computer fails to recognize my input

Question

package programlearning;
import java.util.Scanner;
public class Passwordtest {

private static Scanner Password;

public static void main(String[] args) {
System.out.println("Input Password Please");
Password = new Scanner(System.in);
String x= Password.nextLine();
if(x== "lolz"){
System.out.println("Password is Correct");
}
else{
System.out.println("Wrong");
}
}
}
I tried to make a password program, but whenever I input lolz it says that its wrong?

Answer 1

This will work.
if(x.equals("lolz")){
System.out.println("Password is Correct");
}

Answer 2

why if(x=="lolz") will not work because u r comparing string content not the string references.when we want to compare atring content, we use equals or equalsIgnoreCase mwthod

Answer 3

pls try with if(x.equals("lolz")) instead of if(x== "lolz")

Answer 4

It worked, thank you so much!

Answer 5

answer to the question of mehdi-whenever we assign a value to a string without using new keyword...it first checks the value in string pool..if found it assigns the reference of that object..else creates a new object...so above when you are assigning the lolz string literal to y..same thing happens here and a new string object is being created..and scanner also creates a new object in heap.so references are not same...that why else part is getting executed all the time.

Answer 6

why if(x=="lolz") not work?
what's the problem?

Answer 7

so why this one not work
string y="lolz";
if(x==y)
x and y both are string

Answer 8

might be the case, when we use Scanner object to read input, the string read is stored as new String() object where as in y="lolz" we used as string literal. Though I'm not very sure of thia.

Answer 9

import.java.util.scanner

Answer 10

first take that correct paswrd and store it in variable and then compare with x which is entered paswrd