a + b + "see" + a + b

Question

int a = 2
int b = 3
System.out.print(a+b+"see"+a+b);

This comes up repeatedly in challenges, and although I know the answer by now, I wonder what makes the output of the above code 5see23, instead of either 5see5 or 23see23...

Sorry if it comes up often, thanks for the answer.

Answer 1

I believe, the reason is the order in which the parameters are evaluated.
I imagine that they are evaluated from the left to the right.
So, a + b is evaluated first. Because they are to integers the value is 5.
Then this result (int) is added to the string "see". Now, adding a string to an int
makes the int be casted to string. The result is a concatenation "5see".
Now, this is further concatenated with the other ints which are also
casted to string.

Answer 2

The program evaluates it first from mathematical order, and if it's all the same, then from left to right.
if you want
5see5 - (a+b)+"see"+(a+b);
or if you want
23see23 you need to use the ToString(); method.