Why output is false?

Question

INPUT:
void main()
{
float a=0.7;
if(a==0.7)
printf("true");
else
printf("false");
}
OUTPUT :
false

Answer 1

I think...as he said
at if condition
should be if(a==0.7f)

Because 0.7 is double type in "if" while a is float
(0.7f is float)

Answer 2

I'm not c++ expert though....
So
I can only say that
double is 8 bytes (64 bit)
float is 4 bytes (32 bit)

So yes as @sneeze said They both are different

Answer 3

He talk about C So It's C

Answer 4

Sneeze, it still show the output is false.
I want to know that why the output is false.
Generally its output come in "true". But why output is "false".

Answer 5

Data type is different but those values are same, both (0.7).So why if condition doesn't satisfied.

Answer 6

Default the compiler sees 0.7 as a double. Unless you tell the compiler it is a float.

0.7 double is not the same as 0.7 float because they are stored differently in memory and a double has more precission then a float.

Answer 7

https://code.sololearn.com/c53Xx6zPfk07

The float a=0.7; need a "f" to tell the compiler that 0.7 is a float.
I tested it in C#

float a=0.7f;

Hopes it works the same in the language you are working in.

Answer 8

in which language are you working