How can I compare the result of a function with numbers?

Question

This is my code:

def func(×,y)
res = x + y
return = res
print(func(float(input()),float(input()))
if func < 10
print(Hello!)

this is the error: TypeError: unorderable types: func() < int()

Now I understand that I can't compare functions with numbers but I can't understand how to compare the result of the function with numbers. I tried like this:

if func(x,y) < 10
print(hello!)

but it says that x isn't defined.
Can anybody help me with this?

P.S.:I'm sorry for my bad english

Answer 1

You have several syntax errors:

def func(x, y): # missing colon
return x + y

if func(float(input()), float(input())) < 10: # missing colon
print("Hello!") # Hello! needs to be surrounded with quotes

Answer 2

Thank you for your help!

Answer 3

Actually, the error is caused by the fact that you are comparing a function NAME with a number instead of a function RESULT.

"func" is a function name, of type "function"
"func(10,10)" is a function result, of type... whatever you return (in this case, "int").

If you want this to work the way you wrote it, just store the function result in a variable.
myresult=func(float(input()),float(input()))
print(myresult)
if myresult<10:
print('Hello!')

Also, careful with ":" (it's required after "if" or "def"), and with string values (they should be within quotes - see "Hello!").

As for the error received when calling func(x,y), that is simply because you have no variable named "x". Try calling it with actual numbers: func(10,20)

Answer 4

thank you bogdan, that's a good tip.