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I made a very simple program to better grasp recursion but something is confusing me.
#include <iostream> using namespace std; //a function using recursion to add up numbers in a sequence int add(int a) { if (a == 1||a == 2) { return a + add(a+1); } else { return 1; } } int main() { cout << add(1); } Why is the output 4 rather than 6? In the first loop or "run" where a = 1, from my point of view it executes like so: return 1 + 2 = 3 The second and final loop where the parameter is 2: return 3 + 3(2+1) Apologies if my layout is confusing but please help
2 ответов
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1+ (1+2)
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1 + 2 + 1
1 and 2 are the values of a. When a become 3 the loop returns 1