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In the while loop why the value of variable also shown with the other values obtained when the loop is completed.. please reply.
4 ответов
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yesss here it iss.
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int x=1;
while(x<6){
cout<<"number"<<num<<endl;
num=num+1;
}
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can you explain that in the output of this program how do we get the value of the variable declared above...