public class Program { static int div(int a, int b) { if(b == 0) { throw ArithmeticException("Division by Zero"); } else { x = a/b; return x; } } public static void main(String[] args) { int x= div(42,2); System.out.println(x); } } what is wrong with this code ..

Answer 1

The below code is what you're suppose to write.
throw new ArithmeticException("......");

You might also need to declare the throws keyword after the method signature if asked so.

Answer 2

do .... static int div(int a,int b) throws ArithmeticException

Answer 3

use new to create anonymous object of the exception u wanna throw also u may always use try catch block if that won't work

Answer 4

x is undefined inside div method

Answer 5

syntax for throwing an exception is wrong...use 'throw new ArithmeticException("");' instead of throw ArithmeticException("");