How do use scanner.nextLine () and scanner.nextInt ()

Answer 1

@Zawe
nextLine() returns a string.
So, if you want to use it for an int, it will need to be casted. (And likely surrounded with try-catch).

try {
int input = Integer.parseInt(scanner.nextLine());
} catch (InputMisMatchException e){
System.out println("Error.");
}

There's really no point in doing this though. nextInt() already does this, without issues. (Such as spaces)

Answer 2

//importing Scanner//

import java.util.Scanner;

//Creating a scanner object//

Scanner scn = new Scanner(System.in);

//String and int declaration//

String y;
int i;

//initializing String & int variable to scanner//

y= scn.nextLine();
i = scn.nextInt();

//print//

System.out.println(y);
System.out.println(i);

if you ran this code you will get an input screen the first line will be for String variable "y" and the next line will be int variable "i" .

remeber a String uses nextLine() method whilst int uses nextInt() method.

Answer 3

ohh so line can only be used for String?

Answer 4

Don't really know what's catch but i kinda get the idea thank you for the informations.