How to assign 0xFFFF to int16_t correctly?

Question

code:
#include <stdio.h>
#include <stdlib.h>
#include "stdint.h"
using namespace std;

int main() {
int16_t x=-1;
printf("x=%04X\n",x);
return 0;
}
output:
x=FFFFFFFF

How to get x=FFFF here?

Answer 1

I encourage you to use C++'s cout facility instead of printf function.

This code is working fine.

#include <iostream>
#include <stdlib.h>
#include "stdint.h"
using namespace std;

int main() {
int16_t x=-1;
cout << "x = " << hex << x << endl;
return 0;
}
output:

x=ffff

std::hex is a stream manipulator which sets the format flag to hexadecimal.

Answer 2

int i=0xffff;
cout << i << endl;

Adapt to suit :)