Can anyone explain why x didn't assigned to zero at the time of 2nd calling??

Question

#include <iostream>
using namespace std;
class a {
public :
void func() { static int x = 0;
/* x is initialized only once across three calls of func() and the variable will get incremented three times after these calls. The final value of x will be 3. */
x++;
cout<<x; // outputs the value of x
}};
int main() {
a a1;
a1. func();
a1. func();
a1. func ();
return 0; }

Answer 1

Because class object x is declared static, which means that there is only one copy of x for all instances of the class. Declaring a new instance of the class or calling the same method will not result in x being re-initialized.

Answer 2

I guess the output will be 123
x is not re-initialized as 0 because x has been declared as static.

Answer 3

@Shamima I ran it. Yes it was 123

Answer 4

Output please?

Answer 5

hi,
if u declare the variable static then it will remember the previous value of that variable which will be used for next operation.

if u want to reinitialize the value then remove the static keyword.

Answer 6

thank u for this guys