I need guidance for this Swap function

Question

This is my code. I want to swap the original values of A and B.

#include <iostream>
using namespace std;
void Swap (int A, int B);
int main() {
int A=1; int B=2;
cout<<A;
Swap(A,B);
cout<<A;
return 0;
}
void Swap (int A, int B)
{
int cup;
cup = A;
A = B;
B = cup;
}

Answer 1

You are making copies, use a reference instead by adding & after the data type:

void Swap(int& A, int& B){/**/}

and don't forget to do the same in the prototype.

Answer 2

use the second, but pass A and B as reference:
void Swap( int &A, int &B )