CHALLENGE: Alphabets in the right proportion

Question

Input a string in lower-case
If 'a' occurs 0 or 1 time, 'b' occurs 0 or 2 times, 'c' occurs 0 or 3 times, ...... and 'z' occurs 0 or 26 times, then print 'Yes'
Else print 'No'
Input: A string in lower-case
Output: Yes or No
Example:
Input: abbccc
Output: Yes
as a occurs once, b occurs twice and c occurs thrice, rest 0 times
Input: aabccc
Output: No
as a occurs twice which should have been once

All the best!!!🙃🙃🙃

Answer 1

One liner. Also tells you where the problem is.
https://code.sololearn.com/cKL9u1yA4iJf/?ref=app

Answer 2

Here's :
https://code.sololearn.com/cvA9V3DVDSxx/?ref=app

Answer 3

😞😞😞😞😞....

https://code.sololearn.com/ccBGPi6AiA1F/?ref=app

Answer 4

Not a challenge, but your homework @@

Answer 5

string = input()
yes = all(string.count(letter) == ord(letter) - 96 for letter in string)
print("{}".format("Yes" if yes else "No"))

https://code.sololearn.com/cS3V5KuN5r51/#py

Answer 6

@visph
It's a challenge, not my homework
Solve it if you can and want to 😬

Answer 7

😁😀😊😉