output order

Question

i want to how to make the output dependent on its each individual inpu
#include <iostream>
#include <cstdlib>
#include <cmath>
#include <ctime>
using namespace std;

int main()
{
srand(time(0));
int r = rand();
char a,e,i,o,u;
int c = r % 40 + 1;
int v = r % 40 + 41;
int b = r % 40 + 81;
int n = r % 40 + 121;
int m = r % 40 + 161;
cout <<"This program plays a simple random number game.\n";
cout <<"Enter 5 vowel characters(a,e,i,o,u) separated by space: ";

if (cin>>a)
a = c ;
if (cin>>e)
e = v ;
if (cin>>i)
i = b;
if (cin>>o)
o = n;
if (cin>>u)
u = m;
cout <<"The random numbers are "<< c <<" "<<v <<" "<< b<<" " << n<<" " << m;
return 0;
}
Edit & Run

if you run this those codes , you can see that when enter 5 different vowels a, e ,i , o ,u in different position like e ,i ,a u, o the output of the program still stick to the format "a, e,i o ,u" not "e ,i , a ,u ,o" so is there anyway so that outputs of this are in same position as e,i,a,u,o not a,e,i,o,u.

Answer 1

Of course !

Try something like that :
char c;
int vals[5];

try{
for(unsigned i = 0; i < 5; ++i){
cin >> c;
switch(c){
case 'a':
vals[i] = r%40 + 1;
break;
case 'e':
vals[i] = r%40 + 41;
break;
case 'i':
vals[i] = r%40 + 81;
break;
case 'o':
vals[i] = r%40 + 121;
break;
case 'u':
vals[i] = r%40 + 161;
break;
}
}
}catch(...){
cout << "failed to properly read your input" << endl;
return -1;
}

for(unsigned i = 0; i < 5; ++i)
cout << vals[i] << ' ';
cout << '\n';

Answer 2

You are changing a, e, i, o, and u to be the values c, v, b, n, and m respectively without looking at their value. Then, you ignore them completely to print out the values c, v, b, n, and m so your output will always be in order.

@Baptiste code makes more sense and is likely what you wanted.