How to pass 2D array to a function

Question

i want to calculate the addition of 2 2D matrix in function called by main and return type must b 2D array

Answer 1

you need not return a 2d array work like this....

void use2darrayfunction ( int arr [][***] )

in place of *** you have to put some numerical constant....

for example if your array was declared like this in main ()
int arr [10][25];

then call the function like this
use2darrayfunction ( arr );

and the value in the place of *** should be 25

use the array as you want and the original array will change from the function itself....

Answer 2

if you want the array to be treated like an array (without losing the size property) you should do( for a a 2d array of ints ):
template <int N, int M>
void my_function(int (&arr)[N][M]) { ... }

n and m are the sizes of the array

if you dont care about having a pointer, call it like this:
void muy_function(int **arr) { ... }

Answer 3

An example:
void myfunc(int arr2d[5][30])
Returning an int** works in other compilers...

Answer 4

dude....thats wrong....