Write a program to find sum of the series. S= 1+x+x^2+....+x^n.

Answer 1

int x, n;
cin >> x >> n;
cout << ((pow(x, n + 1) - 1) / (x - 1));

Answer 2

here is a function :
... headed files void main etc.
cin>>x;
cin>>n;
int I;
int sum = 0;
for(I=0;I<=n;I++) {
sum+=pow(x,I);
}
cout<<sum;

Answer 3

// math header file included

int x,n;
cin>>x>>n;

// Using sum of n terms of a GP
cout<<'Sum of series: '<<x*(pow(x,n)-1) / x-1;