How to write a program to find a number is even or odd. Print "even" or "odd" on screen conditions : don't use / % conditional statements if else switch and loops for while & do while

Answer 1

std::string array [2] = { "Even", "Odd" };
int a = 10;
cout <<array [ a & 1];

It's solvable and enjoy

Answer 2

are you sure not to use if-else?
without if-else...the question seems unsolvable

Answer 3

it is solvable without if-else

Answer 4

No, any conditional statements are not needed

Answer 5

my mind's not working....anyone got some idea???

Answer 6

I don't think its possible

Answer 7

If it's an integral number you have to check if the last bit is set. If so, it's uneven. Go from there.

Answer 8

no idea , may be its unsolvable