could someone tell me why would the result of *p=*p+4 eqal to 17 ????!!! help

Question

int x = 5;
int *p = &x;

*p = *p + 4;

Answer 1

Actually the que. u r referring is this:--😊

#include <iostream>
using namespace std;

int main()
{

int x = 5;
int *p = &x;
x=x+4; //x=5+4=9 therefore *p=9
x=*p+4;. // x=9+4=13 therefore *p =13
*p = *p + 4;. // finally *p= 13+4 = 17
cout<< *p;
}

this outputs :- 17
😊😊😊 ..I hope this helps

Answer 2

int x = 5;
//assigned 5 to x
int *p = &x;

*p = *p + 4;
//*p is a pointer to an integer value x so the address of x is assigned to the integer pointer
//*p take the value which is present at the address of x which is 5 so int *p=5
now in next step *p=*p+4; so
*p=5+4=9
and the output came as 9

Answer 3

https://code.sololearn.com/cKmi9Os46e5V/?ref=app

Answer 4

@Oma Falk thank you

Answer 5

@GAWEN thank you alot, yes now i got the result is 9 :)

Answer 6

thank u

Answer 7

This really shouldn't come out as 17. Was it from a challenge question or from code playground? If it's from code playground, post your code here.