What is the output of the code:

Question

int x=1;
cout <<(x++ + ++x);
cout <<x;

Answer 1

43

Answer 2

As x++ first gives number then increments while ++x will increment then give number..

Answer 3

UB
https://www.sololearn.com/Discuss/835390/?ref=app

Answer 4

⁴

Answer 5

4

Answer 6

yes

Answer 7

@$hardul Birje, (x++ + ++x) produces undefined behavior. The expression modifies x twice in one sequence point. This produces undefined behaviour. And UB means that literally anything can happen. See the links from the answer, I've linked here, for more info on this topic. But in a nutshell, sequence point in c++ is a point where you may be sure, that all the side effects of all the operations, performed before it, have taken effect. For example, if you write x++, you may be sure that x is incremented, only at the next SP. Changing something more then once, during one SP, results in UB. There is a complete list of things that do and don't create SP in c++, somewhere in the links I've provided in the linked answer below/above. For example, arithmetic operators or function parameter separator "," don't, end of statement (;), comma operator - do.