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My code was :- float(210*input("enter a number")) take the number as 2 ,can someone tell me y that output..?
Basic question
11 ответов
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The input is a string so %210*input("enter a number")% evaluates to %210*"2"%, i.e. a string of 210 "2" char. Converted to a float the resut is: 2.2222222222222224e+209 (on my machine).
If you expected 420.0 your code should be %print(210*float(input("enter a number")))%
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convert directly to float the input: %float(input("enter a number"))%
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You already have your answer so this is just clarification.
The NUMBER 2 is stored in memory as binary:
0000 0010 (2)
The STRING '2' is stored in memory as binary:
0011 1000 (50)
Because the symbol '2' is at ASCII position 50. Strings take more space to represent than numbers, because the symbols are recorded, not the number you see. Taking integer 50 as an additional example:
50 = 0011 1000 (8 bits)
'50' = ASCII '5' (53) followed by ASCII '0' (48) (total 16 bits)
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In this case 420.0. In the exercise there's float("210"*input("Enter the number")) and the input was 2. If you consider 210 as a string (this for "...") you repeat the string twice. With the function "float" you obtained 210210.0
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Perphaps for the % that you put before and after the code. I'm not an expert.
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Happy to help.
If an answer satisfy you it is a good habit to upvote it.
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ans will be 210210.0, since 210 is an integer value but by default input taken from user is in string format, in this case you are not converting the input string, so ans seems to be..
210 * "2" = 210210
int * str = str
so final ans will be 210210.0, as you are converting it to float
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but for the code that I asked ,idle shows output as 2.2222222222222222224e+209
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No no I didn't put that in the code that's just to tell u guys the code ,it's like comment ,The code I wrote was without those % ,well anyways thanks for ur time
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@jean Yeah that's the answer that I got on my PC too ,but the input is 2 so isn't that a number rather a string ,so shouldn't the answer be float(210*2)??
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ohhh yeah I get it now thanks Jean !